Using Boolean expressions as arguments on Xtext -

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i'm trying create grammar on xtext allows pass boolean expression argument special function gets only boolean parameters (implicitly, without declaring it's boolean type).

for example:

somefunction(...){    foo(4>3, a==b) }  foo(arg1,arg2) {    //do arg1 , arg2 }

do have simple example demonstrates how it?

thank you.

from question not quite clear actual problem is.

if building grammar expression: use starting point

expression:     orexpression ;     orexpression returns expression:     andexpression ({orexpression.left=current} "||" right=andexpression)*   ;     andexpression returns expression:     comparisonexpression ({andexpression.left=current} "&&" right=comparisonexpression)*   ;  comparisonexpression returns expression:     primaryexpression ({comparisonexpression.left=current} operator=("<"|"<="|"=="|">="|">") right=primaryexpression)* ;  primaryexpression returns expression:     "(" expression ")"     | literal ;  literal returns expression:     {literal} value="true" | "false" | int ;

see insights https://typefox.io/parsing-expressions-with-xtext

if building typesystem have @ http://xsemantics.sourceforge.net/


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