Const member function and typedef, C++ -

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suppose want declare const member function via typedef:

typedef int fc() const; typedef int f();  struct {    fc fc;         // fine, have 'int fc() const'    const f fc;    // not fine, 'const' ignored, have 'int fc()' };

since const ignored program compiles fine. why const ignored function? since can form const pointer in way thing can think of 'c heritage'. standard it?

c++ 14 standard, [dcl.fct] pt. 7:

the effect of cv-qualifier-seq in function declarator not same adding cv-qualification on top of function type. in latter case, cv-qualifiers ignored. [ note: function type has cv-qualifier-seq not cv-qualified type; there no cv-qualified function types. — end note ]

example:

typedef void f();  struct s {     const f f; // ok: equivalent to: void f(); };

so, correct behavior.


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