Ruby While Loop -

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i created program in ruby:

print "grandma: something: "  while user_input = gets.chomp #loop while getting user input   case user_input    when user_input.upcase     puts "no, not since! " + rand(1930..1950).to_s     break    when user_input = 'bye'     puts "good bye!"     break    else     puts "huh?!  speak up, now!"     print "grandma: something: "   end  end

this user input , when user type upcase or bye exit program.

now issue here need change program when bye 3 times in row time exit program , not once. how can modify program that?

you need counter that's initialized outside loop, , you'll break once counter reaches 3. i've fixed case expression well. if case on user_input, don't need compare user_input in when.

this should trick:

print "grandma: something: " bye_count = 0 while user_input = gets.chomp   case user_input   when user_input.upcase     puts "no, not since! " + rand(1930..1950).to_s     break   when 'bye'     bye_count += 1     if bye_count >= 3       puts 'good bye!'       break     end   else     puts "huh?!  speak up, now!"     print "grandma: something: "   end end

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