how to get a folder name and file name in python -

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i have python program named myscript.py give me list of files , folders in path provided.

import os import sys  def get_files_in_directory(path):     root, dirs, files in os.walk(path):         print(root)         print(dirs)         print(files) path=sys.argv[1] get_files_in_directory(path)

the path provided d:\python\test , there folders , sub folder in can see in output provided below :

c:\python34>python myscript.py "d:\python\test" d:\python\test ['d1', 'd2'] [] d:\python\test\d1 ['sd1', 'sd2', 'sd3'] [] d:\python\test\d1\sd1 [] ['f1.bat', 'f2.bat', 'f3.bat'] d:\python\test\d1\sd2 [] ['f1.bat'] d:\python\test\d1\sd3 [] ['f1.bat', 'f2.bat'] d:\python\test\d2 ['sd1', 'sd2'] [] d:\python\test\d2\sd1 [] ['f1.bat', 'f2.bat'] d:\python\test\d2\sd2 [] ['f1.bat']

i need output way :

d1-sd1-f1.bat d1-sd1-f2.bat d1-sd1-f3.bat d1-sd2-f1.bat d1-sd3-f1.bat d1-sd3-f2.bat d2-sd1-f1.bat d2-sd1-f2.bat d2-sd2-f1.bat

how output way.(keep in mind directory structure here example. program should flexible path). how do this. there os command this. can please me solve this? (additional information : using python3.4)

you try using glob module instead:

import glob glob.glob('d:\python\test\d1\*\*\*.bat')

or, filenames

import os import glob [os.path.basename(x) x in glob.glob('d:\python\test\d1\*\*\*.bat')]

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