time in strings format: python -

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i using function bring date consistent in column, goes this

from dateutil.parser import parse def dateconv1(x):    c = parse(x)    return c

so if use as, works fine 

in[15]:dateconv1("1 / 22 / 2016 15:03") out[15]:datetime.datetime(2016, 1, 22, 15, 3)

but when pass in variable 

a= 1 / 22 / 2016 15:03 in[16]:dateconv1(str(a))

it doesn't work, how bring in quotes or string, every appreciating

assuming you talking pandas dataset, can use pandas to_datetime() method:

in [66]: dates = ['1 / 22 / 2016 15:03', 'jul 22 2016 12:32pm', 'jul 22 2016 5:40pm',    ....:          'jul 22 2016 8:31pm', 'jul 23 2016 2:01pm', 'jul 23 2016 7:24pm',    ....:          'jul 24 2016 4:30pm', 'aug 1 2016 4:00pm', 'aug 1 2016 7:49pm']  in [67]: df = pd.dataframe({'d':dates})  in [68]: df.dtypes out[68]: d    object dtype: object

d object - means d column of string (object) dtype

in [69]: df out[69]:                      d 0  1 / 22 / 2016 15:03 1  jul 22 2016 12:32pm 2   jul 22 2016 5:40pm 3   jul 22 2016 8:31pm 4   jul 23 2016 2:01pm 5   jul 23 2016 7:24pm 6   jul 24 2016 4:30pm 7    aug 1 2016 4:00pm 8    aug 1 2016 7:49pm

let's convert datetime dtype:

in [70]: df.d = pd.to_datetime(df.d)  in [71]: df out[71]:                     d 0 2016-01-22 15:03:00 1 2016-07-22 12:32:00 2 2016-07-22 17:40:00 3 2016-07-22 20:31:00 4 2016-07-23 14:01:00 5 2016-07-23 19:24:00 6 2016-07-24 16:30:00 7 2016-08-01 16:00:00 8 2016-08-01 19:49:00

check dtype again:

in [72]: df.dtypes out[72]: d    datetime64[ns] dtype: object

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