java - how to ignore the exception and continue to next value -

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hi trying pass list of values google api.if api throws exceptions, comes out of loop.i need coninue next value if throws error.my code below.

while (iterator.hasnext()) {        object element = iterator.next();        string postcode = element.tostring().trim();        string latlongs[] = getlatlongpositions(postcode);        system.out.println("latitude: " + latlongs[0] + " , longitude: " + latlongs[1]);        system.out.println(postcode);    }     public static string[] getlatlongpositions(string address) throws exception {         int responsecode = 0;        string api = "http://maps.googleapis.com/maps/api/geocode/xml?address=" + urlencoder.encode(address, "utf-8") + "&sensor=true";        url url = new url(api);        httpurlconnection httpconnection = (httpurlconnection) url.openconnection();        httpconnection.connect();        responsecode = httpconnection.getresponsecode();        if (responsecode == 200) {            documentbuilder builder = documentbuilderfactory.newinstance().newdocumentbuilder();;            org.w3c.dom.document document = builder.parse(httpconnection.getinputstream());            xpathfactory xpathfactory = xpathfactory.newinstance();            xpath xpath = xpathfactory.newxpath();            xpathexpression expr = xpath.compile("/geocoderesponse/status");            string status = (string) expr.evaluate(document, xpathconstants.string);            if (status.equals("ok")) {                expr = xpath.compile("//geometry/location/lat");                string latitude = (string) expr.evaluate(document, xpathconstants.string);                expr = xpath.compile("//geometry/location/lng");                string longitude = (string) expr.evaluate(document, xpathconstants.string);                return new string[] {                    latitude, longitude                };            } else {                 throw new exception("error api - response status: " + status);            }        }        return null;    }

even if mention return null instead of throw new exception.it shows null pointer exception.any appreciated.

put try/catch around part

... try{     string latlongs[] = getlatlongpositions(postcode);     system.out.println("latitude: " + latlongs[0] + " , longitude: " + latlongs[1]);     system.out.println(postcode); }catch(exception e){     ... }

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