android - How to read a column value in parse.com without accessing an object or a pointer -

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by using code, not able 'name' unless use objectid = xj34weo.
suggest way, if not, @ least using pointer.

//parse query initialization  final parsequery<parseobject> query = parsequery.getquery("myusers");  //to check row has "number"="1234" query.whereequalto("number", "1234");  query.findinbackground(new findcallback<parseobject>() {      public void done(list<parseobject> employees, parseexception e) {         if (e == null) {              try {                  //xj34we0 objectid                  query.get("xj34weo").get("name") + "");              } catch (parseexception pe) {}           }       } });

are trying employee object number?

you have list<parseobject>, use it. 

query.findinbackground(new findcallback<parseobject>() {      public void done(list<parseobject> employees, parseexception e) {         if (e == null && employees.size() > 0) {              try {                  string name = employees.get(0).get("name");                 log.d("parse", name);             } catch (parseexception pe) {}           }       } });

Comments

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    This article is read a column value on the website without accessing the pointer objects. The article is very informative for us.

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